Question

find the value of p for which (X + 1) is a factor of the polynomial p (x) =x cube + t x square + 142 X - 120 ​

Answer 1

Answer:16.21

Step-by-step explanation:zero of (x+1)=-1

-1*-1*-1+t*t+142*-1-120=0

=-1+t*t -142-120=0

=-263+t^2=0

=t^2=263

=t=16.21