Find the value of “p” from the polynomial x2 + 3x + p, if one of the zeroes of the polynomial is 2.
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As it's given zeroes of polynomial is 2.
We know that that if α is a zero of the polynomial p(x), then p(α) = 0
Now, substituting x = 2 in x² + 3x + p or p(x).
⇒2² + 3(2) + p = 0
⇒4 + 3 × 2 + p = 0
⇒4 + 6 + p = 0
⇒10 + p = 0
⇒p = 0 - 10
⇒p = - 10
∴ The Required value of p is - 10.
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