Question

find the value of p if one of the root of quadratic equation 5x² + (3p+2)x + 15 = 0 is 5​

Answer 1

Given that 5 is a root of the quadratic equation 5x²+(3p+2)x+15=0

Implies,

x=5

Now,

5x²+(3p+2)x+15=0

→5(5)²+(3p+2)5+15=0

→125+15+10+15p=0

→15p+150=0

→p= -150/15

→p= -10

Then,

The equation would be:

5x²+(3p+2)x+15=0

»5x²+[3(-10)+2]x+15=0

»5x²-28x+15=0

Answer 2

Answer:-

According to the given quadratic equation5x²+(3p+2)x+15=0

$x=5$

5x²+(3p+2)x+15=0

5(5)²+(3p+2)5+15=0

$125+15+10+15p=0$

$15p+150=0$

$p= -150/15$

$p= -10$

5x²+(3p+2)x+15=0

5x²+(3(-10)+2)x+15=0

5x²-28x+15=0

$Error-free-Answer$

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