Question

Find the value of p if the median of the following frequency distribution is 50
Class 20-30 30-40 40-50 50-60 60-70 70-80
Frequency 25
15
P
6
24
12
80-90
8
2 TL
C 1​

Answer 1

Answer:

Step-by-step explanation:

As per the attached image  

The median 50 lies in the range 50-60

So here we have

l=50, n=(p+90)

n/2 = p/2+45

cf = p+40

f = 6

h = 10

$We\ know \ that \\\\Median = l + \frac {(\frac n2-cf)}{f} \times h\\\\50=50+ \frac {(\frac p2+45-(p+40))}{f} \times 10\\\\Hence\\\\\frac {(\frac p2+45-(p+40))}{f} \times 10=0\\\\\frac p2+45-(p+40)=0\\\\\frac p2+45-p-40)=0\\\\\frac p2=5\\\\p=10$