if the area of a rombhus is 48cmsq.and one of its diagnal is 12 cm find the side of rombhus
Answers
Step-by-step explanation:
) It is given that
Area of rhombus = 480cm
2
It can be written as
2
1
×diagonal1×diagonal2=480
So we get
2
1
×48×diagonal2=480
On further calculation
Diagonal 2 = 20cm
(ii) Consider AC = 48cm and BD = 20cm
The diagonals of a rhombus bisect at right angles
Consider Δ AOD
Using the Pythagoras theorem
AD
2
=OD
2
+AO
2
By substituting the values
AD
2
=24
2
+10
2
On further calculation
AD
2
=576+100
By addition
AD
2
=676
By taking out the square root
AD=
676
So we get
AD = 26cm
We know that AD = BC = CD = AD = 26cm
Therefore, the length of each side of rhombus is 26cm.
(iii) We know that
Perimeter of a rhombus = 4 (side)
By substituting the value
Perimeter of a rhombus = 4 (26)
So we get
Perimeter of a rhombus = 104 cm
Answer:
Answer
Open in answr app
(i) It is given that
Area of rhombus = 480cm
2
It can be written as
2
1
×diagonal1×diagonal2=480
So we get
2
1
×48×diagonal2=480
On further calculation
Diagonal 2 = 20cm
(ii) Consider AC = 48cm and BD = 20cm
The diagonals of a rhombus bisect at right angles
Consider Δ AOD
Using the Pythagoras theorem
AD
2
=OD
2
+AO
2
By substituting the values
AD
2
=24
2
+10
2
On further calculation
AD
2
=576+100
By addition
AD
2
=676
By taking out the square root
AD=
676
So we get
AD = 26cm
We know that AD = BC = CD = AD = 26cm
Therefore, the length of each side of rhombus is 26cm.
(iii) We know that
Perimeter of a rhombus = 4 (side)
By substituting the value
Perimeter of a rhombus = 4 (26)
So we get
Perimeter of a rhombus = 104 cm