Math, asked by papnaimk, 2 months ago

if the area of a rombhus is 48cmsq.and one of its diagnal is 12 cm find the side of rombhus​

Answers

Answered by chiranthana007
1

Step-by-step explanation:

) It is given that

Area of rhombus = 480cm

2

It can be written as

2

1

×diagonal1×diagonal2=480

So we get

2

1

×48×diagonal2=480

On further calculation

Diagonal 2 = 20cm

(ii) Consider AC = 48cm and BD = 20cm

The diagonals of a rhombus bisect at right angles

Consider Δ AOD

Using the Pythagoras theorem

AD

2

=OD

2

+AO

2

By substituting the values

AD

2

=24

2

+10

2

On further calculation

AD

2

=576+100

By addition

AD

2

=676

By taking out the square root

AD=

676

So we get

AD = 26cm

We know that AD = BC = CD = AD = 26cm

Therefore, the length of each side of rhombus is 26cm.

(iii) We know that

Perimeter of a rhombus = 4 (side)

By substituting the value

Perimeter of a rhombus = 4 (26)

So we get

Perimeter of a rhombus = 104 cm

Answered by study12345677890
3

Answer:

Answer

Open in answr app

(i) It is given that

Area of rhombus = 480cm

2

It can be written as

2

1

×diagonal1×diagonal2=480

So we get

2

1

×48×diagonal2=480

On further calculation

Diagonal 2 = 20cm

(ii) Consider AC = 48cm and BD = 20cm

The diagonals of a rhombus bisect at right angles

Consider Δ AOD

Using the Pythagoras theorem

AD

2

=OD

2

+AO

2

By substituting the values

AD

2

=24

2

+10

2

On further calculation

AD

2

=576+100

By addition

AD

2

=676

By taking out the square root

AD=

676

So we get

AD = 26cm

We know that AD = BC = CD = AD = 26cm

Therefore, the length of each side of rhombus is 26cm.

(iii) We know that

Perimeter of a rhombus = 4 (side)

By substituting the value

Perimeter of a rhombus = 4 (26)

So we get

Perimeter of a rhombus = 104 cm

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