Find the value of p if the median of the following frequency distribution is 50
Class frequency
20-30 25
30-40 15
40-50 p
50-60 6
60-70 24
70-80 12
80-90 8
Answers
Answer:
CLASS INTERVAL FREQUENCY CF
20-30 25 25
30-40 15 40
40-50 p 40+P
50-60 6 46+P
60-70 24 70+P
70-80 12 82+P
80-90 8 90+P
L = 50 , F = 6 , CF = 40+P , H = 10
MEDIAN = L + (N/2-CF)/F × H
MEDIAN = 50 + (90+P/2 - [40+P]) / 6 × 10
MEDIAN = 50 + (90+P-80-2P/2) / 6 × 10
50 = 50 + (10-P / 2) /6 × 10
==> 50-50 = 10-P/2 × 1/6 × 10
==> 0 = 10-P/12 × 10
==> 0 = 10-P/1.2
==> 0×1.2 = 10-P
==> 0 = 10-P
==> -10 = -P
==> P = 10
Answer:
Answer:
CLASS INTERVAL FREQUENCY CF
20-30 25 25
30-40 15 40
40-50 p 40+P
50-60 6 46+P
60-70 24 70+P
70-80 12 82+P
80-90 8 90+P
L = 50 , F = 6 , CF = 40+P , H = 10
MEDIAN = L + (N/2-CF)/F × H
MEDIAN = 50 + (90+P/2 - [40+P]) / 6 × 10
MEDIAN = 50 + (90+P-80-2P/2) / 6 × 10
50 = 50 + (10-P / 2) /6 × 10
==> 50-50 = 10-P/2 × 1/6 × 10
==> 0 = 10-P/12 × 10
==> 0 = 10-P/1.2
==> 0×1.2 = 10-P
==> 0 = 10-P
==> -10 = -P
==> P = 10