Math, asked by deepanshu3500, 1 year ago

Find the value of p if the numbers x, 2x+p,3x+6 are 3 consecutive terms of an Ap

Answers

Answered by utu4sungh
1

Answer:

Step-by-step explanation:

AP is X,2x+p,3x+6

In an AP a2-a1=a3-a2

=> (2x+p)-x= 3x+6-(2x+p)

2x+p-x= 3x+6-2x-p

2x+2x-3x-x=-p -p+6

0=-2p+6

-2p =-6

P=3

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