Find the value of p if the numbers x, 2x+p,3x+6 are 3 consecutive terms of an Ap
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Step-by-step explanation:
AP is X,2x+p,3x+6
In an AP a2-a1=a3-a2
=> (2x+p)-x= 3x+6-(2x+p)
2x+p-x= 3x+6-2x-p
2x+2x-3x-x=-p -p+6
0=-2p+6
-2p =-6
P=3
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