find the value of p if the numbers x, 2x+p, 3x+6 are the three consecutive terms of an A.P
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We know,
Common Difference of 2 consecutive numbers of an AP are always equal.
so,
(2x+p) - (x) = (3x+6) - (2x+p)
=> x+p = x-p+6
=> p+p = 6
=> p = 3
3 is the value of p.
Common Difference of 2 consecutive numbers of an AP are always equal.
so,
(2x+p) - (x) = (3x+6) - (2x+p)
=> x+p = x-p+6
=> p+p = 6
=> p = 3
3 is the value of p.
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