Question

Find the value of p if the straight line px+3y-12=0 and 3y-4x+7=0 are parallel to each other

Answer 1

Answer:

since lines are parallel

therefore

$\frac{p}{ - 4} = \frac{3}{3} \\ \frac{p}{ - 4} = 1 \\ p = - 4$

Answer 2

Answer:

p = -4

Step-by-step explanation:

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