Question

Find the value of p if the value of x²-3x²-px-5 is equal to 23 when x = -2.​

Answer 1

• As per the data given in the question, we have to find the value of the expression.

       Given data:- $x=-2.$

       To find:- Value of the expression $x^{2} -3x^{2} -px-5=23.$

       Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:

• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step 2:-then we Simplify the equation in LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation.
• By using the transposition method.

          put the value of $x=-2$ in given equation we get,

             $x^{2} -3x^{2} -px-5=23\\\Rightarrow (-2)^{2}-3(-2)^{2}-p(-2)-5=23 \\\Rightarrow 4-3(-2)^{2}-p(-2)-5=23\\\Rightarrow 4-12+2 p-5=23 \\\Rightarrow -13+2 p=23\\\Rightarrow 2p=23+13\\\Rightarrow 2p=36\\\Rightarrow p=\frac{36}{2} \\\Rightarrow p=18.$

           Hence we will get the value $p=18.$

Answer 2

Given: The equation is$x^{2} -3x^{2} -px-5=23$ and the value of$x=-2$.

We have to find the value of p.

We are solving in the following way:

From the given statement, we have the value of x so by putting this value of x in the above equation, we are finding the value of p.

Now,

$x^{2} -3x^{2} -px-5=23$

We have,

$x=-2$

By putting this value in the above equation:

$\Rightarrow -2^{2} -3\times(-2)^{2} -p\times-2-5\\\Rightarrow 4-3\times4+2p-5\\\Rightarrow 4-12+2p-5\\\Rightarrow -8+2p-5\\\Rightarrow 2p-13=23\\\Rightarrow 2p=23+13\\\Rightarrow 2p=36\\\\\Rightarrow p=\frac{36}{2}$

Solving the above equation further we get,

$\Rightarrow p=18$

Hence, the value of 'p' will be$18$.