Question

find the value of p, if (x-2) is a factor of a polynomial x^3-px^2+12​

Answer 1

Answer:

p=5

Step-by-step explanation:

ifx-2=0

x=2

x³-px²+12=0

putting the value of x

2³-p2²+12=0

8-4p+12=0

-4p+20=0

-4p=-20

p=-20/-4

p=5

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