Question

Find the value of p if x3 +6x2+4x+p is exactly divisible by 2​

Answer 1

ANSWER :

given - x^3+6x^2+4x+p is divisible by 2

x=2 ; x-2=0

Now by substituting value-

p(x) = (2) ^3 + 6(2) ^2+4(2) +p

p(x) = 8+24+8+p

p(x) =40+p

therefore 40+p=0

p=40

HOPE IT HELPS YOU ❤