Question

Find the value of p if x³ - px +10x² - 6 =5 for x =-1​

Answer 1

Given,

• Value of x {for which p(x) is 0} = -1

$\rm{}p(x) = {x}^{3} - px + {10x}^{2} - 6$

To find : Value of p in p(x)

✓✓ SOLUTION ✓✓

Putting the value of x in p(x), we get,

$\tt = > {( - 1)}^{2} - p( - 1) + {10( - 1)}^{2} - 6 = 0 \\ \tt = > \: \: \: \: - 1 + p + 10 - 6 = 0 \\ \tt = > \: \: \: \: \: p + 10 - 7 = 0 \\ \tt = > \: \: \: \: \: p + (10 - 7) = 0 \\ \tt= > \: \: \: \: p + 3 = 0 \\ \tt = > \: \: \: \: \: \: \: \: \: \: \: p = - 3$

Hence,

• Required value of p is -3