Question

Find the value of p in each of the following.....​

Answer 1

Answer: (a) 3/2 (b) 7

Step-by-step explanation:

(a) $7^{2p} \div 343 = 1$

$\dfrac{7^{2p} }{343} = 1$

$\dfrac{7^{2p} }{7^{3} } = 1$

$7^{2p-3} = 1$

$7^{2p-3} = 7^{0}$

$2p - 3 =0$

$2p = 3$

$p = \dfrac{3}{2}$

∴ p = 3/2

(b) $(3^{p})^{3} \times 9^{2} \times 243^{-5} = 1$

$(3^{p})^{3} \times (3^{2})^{2} \times (3^5)^{-5} = 1$

$3^{3p} \times 3^{4} \times 3^{-25} = 1$

${3^{3p+4+(-25)} = 1$

${3^{3p+4-25} = 1$

${3^{3p-21} = 1$

$3^{3p-21} = 3^0$

$3p-21 = 0$

$3p = 21$

$p = \dfrac{21}{3}$

$p = 7$

∴ p = 7

Answer 2

Answer:

kyo app sona nahi chahte ki nind nahi a rahi hai