Question

Find the value of p Px2-3x+5=0 that has two equal roots

Answer 1

Heya !!




P( X ) = PX² - 3X + 5 = 0



This equation is of the form of AX²+BX + C = 0 , Where a = P , B = -3 and C = 5.



Therefore,


Discriminant ( D ) = B²-4AC


=> (-3)² - 4 × P × 5



=> 9 - 20P


For equal roots , we must have :

D = 0



9 - 20P = 0



-20P = -9



P = 9/20.

Answer 2

Given,

It is given that px² - 3x + 5 = 0.

To find,

We have to find the value of p.

Solution,

The value of p px² - 3x + 5 = 0 that has two equal roots is 9/20.

We can simply find the value of p by using the discriminant,

It is given that two roots are equal, then the determinant must be zero.

       px² - 3x + 5 = 0

       D = b² - 4ac

       D = (-3)² - 4(p)(5)

       D = 9-20p

According to the given condition, two roots are equal then D = 0.

9-20p = 0

  -20p = -9

       p = 9/20

Hence, the value of p  px² - 3x + 5 = 0 that has two equal roots is 9/20.