Question

Find the value of P-Q+8 if P=m2+3m and Q=-m2+3m-2.

Answer 1

I hope this is Ur answer....

Answer 2

Given:

$P=m^{2} + 3m$ -------(i)

$Q = - m^{2} + 3m -2$ --------(ii)

To find the value of P - Q + 8

Now, P - Q + 8 = $( m^{2} +3m) - (-m^{2} +3m -2)$ + 8

or, P - Q +8 = $m^{2} +3m +m^{2} -3m +2 +8$

or, P - Q +8 = $2m^{2} +10$

or, P - Q +8 = $= 2(m^{2} +5)$

Hence, the required value of given expression ( P - Q + 8) will be $2 (m^{2} +5)$