Find the value of p so.That three lines 3x+y-2=0, px+2y-3=0 and 2x-y-3=0 may intersect at one point
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Given:
3x + y - 2 = 0 ——> 1
px + 2y - 3 = 0 ——> 2
2x - y - 3 = 0 ——> 3
Solve for x & y, using equations 1 & 3,
3x + y - 2 = 0
2x - y - 3 = 0
———————
5x - 5 = 0
5x = 5
x = 1 ——> 4
y = -1 ——> 5
Substitute 4 & 5 in equation 2,
p(1) + 2(-1) - 3 = 0
p -2 -3 = 0
p - 5 = 0
p = 5 ——> Answer
3x + y - 2 = 0 ——> 1
px + 2y - 3 = 0 ——> 2
2x - y - 3 = 0 ——> 3
Solve for x & y, using equations 1 & 3,
3x + y - 2 = 0
2x - y - 3 = 0
———————
5x - 5 = 0
5x = 5
x = 1 ——> 4
y = -1 ——> 5
Substitute 4 & 5 in equation 2,
p(1) + 2(-1) - 3 = 0
p -2 -3 = 0
p - 5 = 0
p = 5 ——> Answer
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