Question

find the value of p such that (p-12)x²-2(p-12)x+2=0 has equal roots​

Answer 1

Answer:

p=14

Step-by-step explanation:

p−12)x²-2(p−12)x+2=0

For quadratic equation to has equal roots

b²=4ac

4(p−12)²=4(p−12)(2)

p−12=2

p=2+12

p=14

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