find the value of p(x)=7x3-8x2-2x+1. x=1/2
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Answered by
4
Step-by-step explanation:
v) 6x2 − 3 − 7x
(v) p(x)=x2+2
√
2
x-6
(vi) q(x)=
√
3
x2+10x+7
√
3
(vii)f(x)=x2-(
√
3
+1) x+
√
3
(viii) g(x) = a(x2 + 1) − x(a2 + 1)
(ix) h(s)=2s2-(1+2
√
2
)s+
√
2
(x) f(v)=v2+4
√
3
v-15
(xi) p(y)=y2+
3
√
5
2
y-5
(xii) q(y)=7y2-
11
3
y-
2
3
ANSWER:
(i) We have,
f(x) = x2 − 2x − 8
f(x) = x2 + 2x − 4x − 8
f(x) = x (x + 2) − 4(x + 2)
f(x) = (x + 2) (x − 4)
The zeros of f(x) are given by
f(x) = 0
x2 − 2x − 8 = 0
(x + 2) (x − 4) = 0
x + 2 = 0
x = −2
Or
x − 4 = 0
x = 4
Thus, the zeros of f(x) = x2 − 2x − 8 are α = −2 and β = 4
Now,
and
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1
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