Question

Find the value of P (x)
P(x) = x² + 2x-5 at P (1)​

Answer 1

Answer:

Given, P(x)= x^2 + 2x-5

now, P(1)= 1^2+ 2×1-5

= 1+ (-3) = (-2)

Therefore the value of P(x) at x=1 is:- (-2)

Answer 2

Answer:

$\large\mathrm\pink{Given:}$

$\large\mathrm{p(x) = x^2 + 2x - 5 }$

$\huge\mathrm\pink{solution :}$

if X = 1, then,

$\mathrm{P(x) = X^2 + 2x - 5 } \\ \\ \implies P(1) = 1^2 + 2(1) - 5 \\ \\ \implies P(1) = 1 + 2- 5 \\ \\ \implies \fbox{-2}$