Math, asked by sandya134134134, 5 hours ago

Find the value of P(x)=x2-2x -8 at
x =1 and x=0

Answers

Answered by sirireddykristipati
0

Step-by-step explanation:

at x = 1

1 - 2 - 8 = -9

at x = 0

0 - 0 -8 = -8

Answered by mudrajain8th
0

Answer:

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Step-by-step explanation:

when x=1

P(x)=x2-2x -8

     =1*1-2*1-8

     =1-2-8

     =-9 answer

when x=0

P(x)=x2-2x -8

    =0-0-0

    =0 answer

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