Find the value of p:- x2 - 2px+1 = 0 where this equation has no real roots
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Hi ,
Compare x² - 2px + 1 = 0 with
ax² + bx + c = 0.,
a = 1 ,
b = - 2p ,
c = 1 ,
If roots are not real then
discreaminant < 0
b² - 4ac < 0
( - 2p )² - 4 × 1 × 1 < 0
4p² - 4 < 0
4p² < 4
p² < 4/4
p ² < 1
p < ± 1
Therefore ,
If p < ±1 then the equation has
no real roots.
I hope this helps you.
: )
Compare x² - 2px + 1 = 0 with
ax² + bx + c = 0.,
a = 1 ,
b = - 2p ,
c = 1 ,
If roots are not real then
discreaminant < 0
b² - 4ac < 0
( - 2p )² - 4 × 1 × 1 < 0
4p² - 4 < 0
4p² < 4
p² < 4/4
p ² < 1
p < ± 1
Therefore ,
If p < ±1 then the equation has
no real roots.
I hope this helps you.
: )
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