Find the value of p(y) = 5y2 – 3y + 7 at y = – 1
Answers
Answered by
6
5y^2-3y+7=0 ; y=-1
5*(-1)^2 - 3*-1+7
5*1-(-3)+7
5+3+7
15
:: the answer is 15
Answered by
3
Answer:
4
is your answer hope it will help you.
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