find the value of p { z ] when p [ x } = x square - 3x + 2.
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If p(x) = x²- 3x + 2, then what is the value of p (0) + p (2)
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Given: p(x) = x²- 3x + 2
p(0) = 0² - (3 * 0) + 2 = 0 - 0 + 2 = 2
p(2) = 2² - (3 * 2) + 2 = 4 - 6 + 2 = 0
p(0) + p (2) = 2 + 0 = 2
Ans. = 2
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