Math, asked by arorakhushi821, 11 months ago

find the value of polynomial 8x³-6x²+2 at x=1​

Answers

Answered by sureka5
25

Answer:

the answer will be 4

Step-by-step explanation:

8x3-6x^2+2 = 8(1)^3 - 6(1)^2 + 2

= 8 - 6 + 2

= 10 - 6

= 4

?ℍ

Answered by RvChaudharY50
8
  • The value of polynomial 8x³ - 6x² + 2 at x = 1 is equal to 4 .

To Find :- The value of polynomial 8x³ - 6x² + 2 at x = 1 ?

Solution :-

given that,

→ p(x) = 8x³ - 6x² + 2

putting x = 1 we get,

→ p(1) = 8(1)³ - 6(1)² + 2

→ p(1) = 8 × 1 - 6 × 1 + 2

→ p(1) = 8 - 6 + 2

→ p(1) = 10 - 6

→ p(1) = 4 (Ans.)

Hen the value of the given polynomial at x = 1 is equal to 4 .

Extra knowledge :- If A•x² + B•x + C = 0, is any quadratic equation, then its discriminant is given by :-

  • D = B^2 - 4•A•C

• If D = 0 , then the given quadratic equation has real and equal roots.

• If D > 0 , then the given quadratic equation has real and distinct roots.

• If D < 0 , then the given quadratic equation has unreal (imaginary) roots.

Learn more :-

Let a, b and c be non-zero real numbers satisfying (a³)/(b³ + c³) + (b³)/(c³ + a³) + (c³)/(a³ + b³)

https://brainly.in/question/40626097

https://brainly.in/question/20858452

if a²+ab+b²=25

b²+bc+c²=49

c²+ca+a²=64

Then, find the value of

(a+b+c)² - 100 = __

https://brainly.in/question/16231132

Similar questions