Question

Find the value of polynomial p(x) = 2+x+2x2-x2 at x=2​

Answer 1

Answer:

p(X)= 2+2+2(2)2-2(2)

2+2+8-4

4+8-4

8

Step-by-step explanation:

i hope this will help you out

Answer 2

Answer:

$\huge{\underline{\underline{Given→}}}$

• $\sf\green{Equation→p(x)=2+x+2x^2-x^2}$

$\huge{\underline{\underline{To\:Find→}}}$

$\sf\purple{→Value\:of\:the\:given\:equation\:at\:x=2}$

$\huge{\underline{\underline{Answer→}}}$

$\bold{\underline{\underline{\dag{Simplification\dag→}}}}$

$2 + x + {2x}^{2} { - x}^{2} \\ = ({2x}^{2} { - x}^{2}) + x + 2 \\ = {x}^{2} + x + 2$

$\displaystyle{\boxed{→x^2+x+2✔}}$

$\bold{\underline{\underline{Value→}}}$

$\mathrm\blue{→x^2+x+2}$

$\mathrm\blue{→(2)^2+2+2}$

$\mathrm\blue{→4+2+2}$

$\mathrm\blue{→4+4}$

$\mathrm\blue{→8}$

$\sf{\boxed{\boxed{\pink{→8✔}}}}$

☞ Hence the value of the given equation at x=2 is 8 which is the required answer.

HOPE IT HELPS.