Math, asked by kakaj14utorje8e, 7 months ago

find the value of polynomial

p(x)=4x²-2x÷3 at x=1​

Answers

Answered by spichhoredot123
1

Answer:

p (x ) = 4 x²-2x÷3

if x = 1

p (1) = 4 (1)²-2(1) ÷3

p = 4-2÷3

p = 12-2 ÷3

p = 10 /3

Answered by BrainlyYuVa
2

✴Answer✴

Find value of :-

  • p(x)=4x²-2x÷3 at x=1.

keep value of X,

=> p(1)= 4(1)²-2×1÷3

=>p(1)= 4-2÷3

=>p(1) = 4 - 2/3

=> p(1) = (12-2)/3

=>p(1) = 10/3

=>

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