Question

find the value of polynomial [tex]5x-4 x^{2} +3
(i) x=0

Answer 1

Your answer is :- 

P(x) = 5x-4x²+3
P(0) = 5x0 - 4x(0)² +3
P(0) = 0-0+3
P(0) = 3

Your answer is 3..............................

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Answer 2

p(x)=5x-4x²+3
p(0)=5(0)-4(0)²+3
p(0)=0-0+3
p(0)=+3