Question

+ Find the value of positive integer n for which n2 + 19n + 48 is a perfect square.​

Answer 1

Step-by-step explanation:

n^2 + 19n + 48 = 0

n^2 + 3n+ 16n + 48 = 0

n (n+3) + 16 (n+3) = 0

(n+3) (n+16) = 0

n+3=0

n=-3

n+16=0

n=-16

Answer 2

this is your answer hope it's helpful for you thankyou