Question

Find the value of px^2 - 50x+p has equal roots.

Answer 1

Heya !!

PX² - 50X + P




Here,


A = P , B = -50 and C = P




Discriminant ( D ) = 0




B²-4AC = 0



(-50)² - 4P² = 0



-4P² = -2500



P² = 2500/4


P = ✓2500/4 = 50/2 = 25




P = 25

Answer 2

Comparing the given equation as ax² + bx + c = 0



Hence, we got

a = p
b = - 50
c = p



Discriminant = b² - 4ac
=> ( -50 )² - 4( p × p )
=> 2500 - 4p²


For equal roots, discriminant = 0


2500 - 4p² = 0

2500/4 = p²

625 = p²

-25 or 25 = p





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