Question

Find the value of R in the following circuit

Answer 1

Explanation: R , 2R , 3R are in parallel to each other  and in series with 5R/11

so 1/R + 1/2R + 1/3R = 6R/11

AND THEN ADD 5R/11 TO 6R/11 = 11R/11 = R

V = IR

12=2 * R

12/2 = R

6= R