Question

find the value of R of the tiny circle ,here R = radius

Note=＞ here ABCD is a square and the radius of the two big circles is same and the tiny circle is touching the side AB , arc AC and arc BD tangentially

Answer 1

let the radius of the circle be x
by Pythagoras theorem
(3+x)²=(1.5)²+(3-x)²
(3+x)²-(3-x)²=(1.5)²
4.3.x=2.25
12x=2.25
x=2.25/12
=225/1200
=9/48(answer)