Math, asked by gayatri5340, 1 year ago

Find the value of (root 4)power -7 * (root 2)power 5

Answers

Answered by DaIncredible
9
Hey friend,
Here is the answer you were looking for:
 { \sqrt{4} }^{ - 7}  \times  { \sqrt{2} }^{5}  \\  \\  =  \frac{1}{ { \sqrt{4} }^{7} }  \times  { \sqrt{2} }^{5}  \\  \\  =  \frac{1}{ \sqrt{4 \times 4 \times 4 \times 4 \times 4 \times 4 \times 4} }  \times   \sqrt{2 \times 2 \times 2 \times 2 \times 2}  \\  \\  =  \frac{1}{4 \times 4 \times 4 \sqrt{4} }  \times 2 \times 2 \sqrt{2}  \\  \\  =  \frac{1}{64 \sqrt{2 \times 2} }  \times 4 \sqrt{2}  \\  \\  =  \frac{4 \sqrt{2} }{64 \times 2}  \\  \\  =  \frac{ \sqrt{2} }{16 \times 2}  \\  \\  =  \frac{ \sqrt{2} }{32}

Hope this helps!!!

@Mahak24

Thanks...
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