find the value of root a, b, c step by step explanation give you 20 points
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Answer:
4 /( 2 + √3 + √7 )= √a +√b -√c
LHS =4 /( 2 + √3 + √7 )
Multiplying the conjugate
=4( 2 - √3 + √7 ) /( 2 + √3 + √7 )( 2 - [√3 + √7 ] )
= 4( 2 - √3 + √7 ) / ( 4 - [√3 + √7 ]^2 )
= 4( 2 - √3 + √7 ) / (4 - [3 + 2√21 + 7 ] )
= 4( 2 - √3 + √7 ) / (4- 3 - 2√21 - 7 ] )
= 4( 2 - √3 + √7 ) / (-6 -2 √21)
=4( 2 - √3 + √7 ) / 2 ( -3 -√21 )
= 2( 2 - √3 + √7 ) / ( -3 -√21 )
= 4 -2 √3 + 2√7 / ( -3 -√21 )
again conjugate
=(4 -2 √3 + 2√7) ( -3 + √21 ) / ( -3 + √21 )( -3 -√21 )
= (-12 + 4√21 + 6√3 -2√63 -6 √7 + 2√147 ) / ( 9 - 21 )
= (-12 + 4√21 + 6√3 -6√7 -6 √7 + 14√3) / (-12 )
=(-12 + 4√21 + 20√3 -12√7 ) / -12
= -1 - √21 / 3 - 5√3 /3 + √7
= -1 - √(7/3) - 5√3 /3 + √7
= (-√3 -√7 - √(25/3 ) + √21) / √3
=(-3 - √21 - √25 + √63) / 3
you would get some idea from this method..........