Question

Two water taps together fill tank in 9 3/18 Tap of larger diameter takes10 hrs less

Answer 1

Let the tap with smaller diameter fills the tank alone in x hours.

Let the tap with larger diameter fills the tank alone in (x – 10) hours.

In 1 hour, the tap with smaller diameter can fill 1/x part of the tank.

In 1 hour, the tap with larger diameter can fill 1/(x – 10) part of the tank.

The tank is filled up in 75/8 hours.

Thus, in 1 hour the taps fill 8/75 part of the tank.

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If x = 25, then (x – 10) = 25 – 10 = 15.

Thus, the tap with smaller diameter fills the tank alone in 25 hours where as the larger diameter fills the tank alone in 15 hours.

here is ur ans hope it helps you.

Answer 2

Answer:By smaller diameter tap fills in 25 hrs.

While larger one fills in 15 hrs.

Solution=let the smaller diameter tap fills the tank alone in x hrs.

And also let the larger diameter tap fills the tank alone in {x-10} hrs

In 1 hr. The smaller diameter tap is filling = 1/x part of the tank

In 1 hr. The larger diameter tap filling in =1/(x-10) part of the tank

The taps takes together to fill the tank =9whole 3/8 hrs. Also 75/8

So in 1 hr it can fill in 8/75hrs

When x=25, then (x-10) =25-10=15

•°•the smaller diameter tap fills the tank in 25 hrs while larger one fills in 15 hrs.....

Hope it will help u

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