Question

find the value of sin 120°
cot 120
sec 120​

Answer 1

. sin 120° = sin (1 × 90° + 30°) = cos 30° = √32√32;

cos 120° = cos (1 × 90° + 30°) = - sin 30° = - 1212; 

tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;

csc 120° = csc (1 × 90° + 30°) = sec 30° = 2√32√3;

sec 120° = sec (1 × 90° + 30°) = - csc 30° = - 2;

tan 120° = tan (1 × 90° + 30°) = - cot 30° = - √3;

cot 120° = cot (1 × 90° + 30°) = - tan 30° = - 1√31√3.

Answer 2

sin 120= cos 30=√3/2

cot 120=-tan 30=-1/√3

sec 120=-cosec 30=-2