Math, asked by Anonymous, 10 months ago

find the value of sin 1380°​

Answers

Answered by pranavkumbhar6866
8

Step-by-step explanation:

1380-3*360=1380-1080=300

sin(1380)=sin(300)=sin(60)=-√3/2 (in Q4 where sin<0)

..

cos(225)=cos(45)=-√2/2 (in Q3 where cos<0)

..

420-360=60

tan(420)=tan(60)=√3 (in Q1 where tan>0)

Answered by Swarup1998
0

The value of \mathsf{sin1380^{o}} is \mathsf{(-\dfrac{\sqrt{3}}{2})}.

Concept to be used:

First of all we must have some trigonometric ideas that would help us solve the problem:

  • In the first and the second quadrant, sin is always positive. In other quadrants, it is negative.

  • In the first and the third quadrant, tan is always positive. In other quadrants, it is negative.

  • In the first and the fourth quadrant, cos is always positive. In other quadrants, it is negative.

Step-by-step explanation:

Now, \mathsf{sin1380^{o}}

\mathsf{=sin(15\times 90^{o}+30^{o})}

  • [ It lies in the fourth quadrant and in fourth quadrant the symbol of \mathsf{sin} is negative and being an odd multiple of \mathsf{90^{o}}, it changes into \mathsf{cos}. ]

\mathsf{=-cos30^{o}}

\mathsf{=-\dfrac{\sqrt{3}}{2}}

#SPJ3

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