Question

find the value of sin 15°+ cos 15°​

Answer 1

Answer:

Finally, we have tan15∘=sin15∘cos15∘=√6−√2√6+√2=(√6−√2)2(√6+√2)(√6−√2)=6+2−2√2√66−2=8−2√124=2−√3. In the triangle ABC, B is a right angle and the other angles are such that if a point E on BC and between B and C is chosen so that BE=BA, then there is a point D on AC and between A and C such that AD=DE=EC.

Explanation:

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