Question

find the value of sin^2 41 + sin^2 49

Answer 1

Here is your answer :-

sin²41 + sin²49 = ?

Solution ,

= sin²41 + sin²49

= sin²(90-49) + sin²49

= cos²49 + sin²49 ( sin²(90- theta) = cos² theta)

= 1

Answer 2

we know by quadrant that
sin (90-A) = cos A & cos (90-A) = sin A
so,
= sin^2 41 + sin^2 49
= sin^2 41 + cos^2 (90-41)
= sin^2 41 + cos^2 41
= 1
[ by trigonometric identity
sin^2 A + cos^2 A =1 ]