Question

find the value of sin^2A×sec^2A​

Answer 1

(sinA)^2×(secA)^2=(sinA)^2×1/(cosA)^2

=(tanA)^2

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Answer 2

${sin}^{2} \times { sec}^{2} \\ = { sin}^{2} \times \frac{1}{ cos^{2} } \\ = \frac{ {sin}^{2} }{ {cos}^{2} } \\ = {tan}^{2} (ans)$

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