Math, asked by sambhavmaheshwari2, 9 months ago

find the value of sin 2a when sin a =12\13​

Answers

Answered by abhi569
8

Answer:

120/169

Step-by-step explanation:

When sinA = 12/13, use pythagoras theorem,

base = √13² - 12² = 5

Hence, cosA = 5/13

We know, sin2A = 2sinAcosA

Hence, here

=> sin2A

=> 2sinAcosA

=> 2(12/13)(5/13)

=> 120/169

Answered by sshailshetty
4

Answer:

120/169

Step-by-step explanation:

If Sin a=12/13

So It means We have to

Sin a

 \binom{12}{13}^{2}

Sin a=

 \binom{120}{169}

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