Find the value of sin 30 degree geometrically.
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Here is your answer ⤵
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For finding the value of sin 30° geometrically, we construct an equilateral triangle ABC of side 2a. From A, we draw perpendicular AD to BC. Now, BD = CD = 1/2 BC = a
In triangle ABD, angle BAD + angle BDA + angle DAB = 180 (BY ANGLE SUM PROPERTY)
⇒ 60°+ BAD + 90° = 180° (Since AD || BC and all angles are 60° in a equilateral triangle)
⇒ BAD = 30°
In Right Triangle,
Sin 30° = BD / AB= a / 2 a = 1/ 2
hence geometrically shown that sin 30 is 1/2
___________________
Hope it helps!
Here is your answer ⤵
__________________
For finding the value of sin 30° geometrically, we construct an equilateral triangle ABC of side 2a. From A, we draw perpendicular AD to BC. Now, BD = CD = 1/2 BC = a
In triangle ABD, angle BAD + angle BDA + angle DAB = 180 (BY ANGLE SUM PROPERTY)
⇒ 60°+ BAD + 90° = 180° (Since AD || BC and all angles are 60° in a equilateral triangle)
⇒ BAD = 30°
In Right Triangle,
Sin 30° = BD / AB= a / 2 a = 1/ 2
hence geometrically shown that sin 30 is 1/2
___________________
Hope it helps!
ADheeraj33:
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