Math, asked by lisahaydon3576, 12 hours ago

Find the value of:sin(-300°)cos^2 (120) + cos^2(-240 )sin^3(370)​

Answers

Answered by dkchakrabarty01
1

Answer:

=-sin300cos^2(180-60)+(-cos240)^2sin^3(360+10)

=-sin(360-60)(-1/2)^2+{(cos(180+60)}^2sin^3(10)

=sin60(1/4)+{-1/2}^2.sin^3(10)

What value of sin 10 to be used?

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