Question

Find the value of sin 3x.sin 6x.sin9x. when x=10°​

Answer 1

Answer:

bhai follow karo to hi dunga answer

Answer 2

Step-by-step explanation:

$given \: x = 10 \\ 3x = 3 \times 10 = 30 \\ 6x = 60 \\ 9x = 90$

substitute in formula

sin3x.sin6x.sin9x

=sin30.sin60.sin90

=1/2×root3/2×1

=

$\sqrt{3} \div 4$