find the value of sin(50+theta)-cos(40-theta)
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sin(50+θ)-cos(40-θ)=sin(90-(50+θ))-cos(40-θ)
=cos(40-θ)-cos(40-θ)
=0
=cos(40-θ)-cos(40-θ)
=0
Rittwotson:
thanks
But cos(90°-(50+ø))=sin50+∅
sorry in the first step it is sin(90-(40-theta)).please change it
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