find the value of sin 60+cos30-tan30
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Answered by
4
Hi ,
Sin60° + cos30° - tan30°
= √3/2 + √3/2 - 1/√3
= 2( √3 /2 ) - 1/√3
= √3 - 1/√3
= [ ( √3 )² - 1 ] / √3
= ( 3 - 1 ) / √3
= 2/√3
I hope this helps you.
:)
Sin60° + cos30° - tan30°
= √3/2 + √3/2 - 1/√3
= 2( √3 /2 ) - 1/√3
= √3 - 1/√3
= [ ( √3 )² - 1 ] / √3
= ( 3 - 1 ) / √3
= 2/√3
I hope this helps you.
:)
Answered by
4
sin60=√3/2
cos30=✓3/2
tan30=1/✓3
Therefore
sani60+cos30-tan30=✓3/2+✓3/2-1/✓3
= 3+3-2/2✓3 =6-2/2✓3 =4/2✓3
=2/✓3 Ans
cos30=✓3/2
tan30=1/✓3
Therefore
sani60+cos30-tan30=✓3/2+✓3/2-1/✓3
= 3+3-2/2✓3 =6-2/2✓3 =4/2✓3
=2/✓3 Ans
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