Find the value of: sin 75°
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Answer:-
Sin 75° = (√3 + 1)/2√2
Solution:
We have to find the value of Sin 75°. Let us some Trigonometric compound ratios before solving this problem.
Sin (A + B) = SinA.CosB+ CosA.SinB
Sin (A - B) = SinA.CosB - CosA.SinB
Sin 75° can be written as Sin(45° + 30°). We will solve the above expression with the help of trigonometric compound ratios.
Sin 75°
0r, Sin(45° + 30°)
0r, Sin45°.Cos30° + Cos45°.Sin30°
0r, (1/√2. √3/2) + ( 1/√2 + 1/2)
0r, {(√3)/2√2 + (2+√2)/2}
0r, (√3 + 1)/2√2
Therefore, the required value of Sin 75° is (√3 + 1)/2√2
Therefore, the required value of Sin 75° is (√3 + 1)/2√2
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