Find the value of (sin θ + cos θ) ²+ (cos θ -sin θ) ²
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Answer:
(sin θ + cos θ) ²+ (cos θ -sin θ) ² = 2
Step-by-step explanation:
= (sin θ + cos θ) ²+ (cos θ -sin θ) ²
= [sin²θ + cos²θ + 2sinθcosθ ] + [sin²θ + cos²θ - 2sinθcosθ]
USING IDENTITY sin²θ + cos²θ = 1
= 1 + 2sinθcosθ + 1 - 2sinθcosθ
= 2 ⇒ ANSWER
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