Math, asked by shubhangini767, 8 months ago

Find the value of (sin θ + cos θ) ²+ (cos θ -sin θ) ²

Answers

Answered by REDPLANET
3

Answer:

(sin θ + cos θ) ²+ (cos θ -sin θ) ² = 2

Step-by-step explanation:

= (sin θ + cos θ) ²+ (cos θ -sin θ) ²

= [sin²θ + cos²θ + 2sinθcosθ ] + [sin²θ + cos²θ - 2sinθcosθ]

USING IDENTITY sin²θ + cos²θ = 1

=  1 + 2sinθcosθ  + 1 - 2sinθcosθ

= 2 ⇒ ANSWER

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