find the value of sin pi by 3
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hello
sin pi/3
= sin 180/3
= sin 60°
= root(3)/2
sin pi/3
= sin 180/3
= sin 60°
= root(3)/2
Answered by
0
Answer:
sin(π3)=√32
Explanation:
π3 Radians =60 Degrees
sin60=√32
To prove this consider an equilateral trigangle ABC of side 2 units as diagram below.
 Ref: "Quora" - With thanks
The bisector of angle A meets side BC at D which is the midpoint of BC.
By Pythagoras:
AB2=AD2+DB2
22=AD2+12→AD=√4−1=√3
Angle B = 60 Degrees
Therefore: sin(60)=ADAB=√32
sin(π3)=√32
Explanation:
π3 Radians =60 Degrees
sin60=√32
To prove this consider an equilateral trigangle ABC of side 2 units as diagram below.
 Ref: "Quora" - With thanks
The bisector of angle A meets side BC at D which is the midpoint of BC.
By Pythagoras:
AB2=AD2+DB2
22=AD2+12→AD=√4−1=√3
Angle B = 60 Degrees
Therefore: sin(60)=ADAB=√32
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