Question

Find the value of sin square 60 degree + cos square 45 degree

Answer 1

Answer:

sin 60=√3/2

sin 60 sq.=(√3/2)²

sin 60 sq=3/4

cos 45=1/√2

cos 45sq.=(1/√2)²

cos 45sq.=1/2

according to question

3/4+1/2

3/4+2/4

5/4

5/4=sin sq.60°+cos sq.45°

Answer 2

The value is 5/4.

Given:

${sin}^{2} {60}^{o} + {cos}^{2} {45}^{o}$

To find:

We have to find its value.

Solution:

The value of sin60° is √3/2.

The value of cos45° is 1/√2

To find the value of the expression ${sin}^{2} {60}^{o} + {cos}^{2} {45}^{o}$ we have to determine the square of √3/2 and the square of 1/√2.

Then we have to add the values.

Thus the value of the expression is-

${\dfrac{\sqrt3}{2}}^{2}+ {\dfrac{1}{\sqrt2}}^{2}$

3/4+1/2

3+2/4

5/4

The value is 5/4.